====== Die Lösung der Weihnachtsgleichung ======

<m>~~~~~~y~=~{\ln(x/m ~-~ sa)}/r^2</m>

<m>\doubleleftright~ r^2y~=~\ln(x/m) ~-~ as</m>

<m>\doubleleftright~ \e^{r^2y} ~=~ x/m ~-~ as</m>

<m>\doubleleftright~ \e^{r^2y} ~+~ as ~=~ x/m</m>

<m>\doubleleftright~ m(\e^{r^2y} ~+~ as) ~=~ x</m>

<m>\doubleleftright~ m\e^{r^2y} ~+~ ams ~=~ x</m>

<m>\doubleleftright~ m \e^{r^2y} ~=~ x~-~ams</m>

also

<m>m \e^{rry} ~=~ x-mas</m>

:-)

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